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Question Number 79413 by rajesh4661kumar@gmail.com last updated on 25/Jan/20
Commented by john santu last updated on 25/Jan/20
(cosxsinxcos2x(cos2x−sin2x))2=14.sin22xcos42x=14tan22xsec22x∫18tan2(2x)d(tan(2x))=124tan3(2x)+c
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