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Question Number 79413 by rajesh4661kumar@gmail.com last updated on 25/Jan/20

Commented by john santu last updated on 25/Jan/20

(((cos xsin x)/(cos 2x(cos^2 x−sin^2 x) )))^2 =  (1/4).((sin^2 2x)/(cos^4 2x)) =(1/4)tan^2 2xsec^2 2x  ∫ (1/8)tan^2 (2x) d(tan(2x)) =  (1/(24))tan^3 (2x) +c

(cosxsinxcos2x(cos2xsin2x))2=14.sin22xcos42x=14tan22xsec22x18tan2(2x)d(tan(2x))=124tan3(2x)+c

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