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Question Number 79423 by Rio Michael last updated on 25/Jan/20
solveforxandysinhx−2coshy=03coshx+6sihny=5
Answered by mr W last updated on 25/Jan/20
coshy=sinhx2...(i)sinhy=56−coshx2...(ii)(i)2−(ii)2:1=sinh2x4−2536+56coshx−cosh2x41=−2536+56coshx−1⇒coshx=9730⇒x=cosh−19730=ln(9730+(9730)2−1)=ln97+850930sinhx=±(9730)2−1=±850930coshy=sinhx2=±850960>1⇒only+⇒y=cosh−1850960=ln4909+850960
Commented by Rio Michael last updated on 27/Jan/20
thankssir,seemslikehyperbolicfunctionsdon′tsuitsimultaneousequations
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