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Question Number 79462 by berket last updated on 25/Jan/20

$$provep\Rightarrow qand\sim q\Rightarrow \sim parelogicaly$$$$equivalentwithouttruthtable$$$$$$

Answered by key of knowledge last updated on 25/Jan/20

$$\mathrm{p}\Rightarrow \mathrm{q}\equiv -\mathrm{p}\vee \mathrm{q}\equiv \mathrm{q}\vee -\mathrm{p}\equiv -\mathrm{q}\Rightarrow -\mathrm{p}$$

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