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Question Number 79500 by ubaydulla last updated on 25/Jan/20
∫(cot2x+cot4x)dx
Answered by john santu last updated on 25/Jan/20
∫cot2x(1+cot2x)dx=∫cot2xcosec2xdx=∫−cot2xd(cotx)=−13cot3x+c
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