Question Number 7960 by tawakalitu last updated on 25/Sep/16 | ||
$$\int\frac{\mathrm{4}\:−\:{x}}{\mathrm{4}\:+\:{x}}\:{dx} \\ $$ | ||
Commented by Yozzia last updated on 25/Sep/16 | ||
$$\int\frac{\mathrm{4}−{x}}{\mathrm{4}+{x}}{dx}=\int\left(\frac{\mathrm{8}}{\mathrm{4}+{x}}−\mathrm{1}\right){dx}=\mathrm{8}{ln}\left({x}+\mathrm{4}\right)−{x}+{c} \\ $$ | ||
Commented by tawakalitu last updated on 25/Sep/16 | ||
$${Thanks}\:{so}\:{much}\:{sir}. \\ $$ | ||
Answered by prakash jain last updated on 02/Oct/16 | ||
$$\mathrm{answer}\:\mathrm{in}\:\mathrm{comments} \\ $$ | ||