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Question Number 79607 by sou99 last updated on 26/Jan/20
Solvethis∫(x−yz)(x2+y2−2xyz)3/2dz
Commented by MJS last updated on 26/Jan/20
∫a+bt(c+dt)3/2dt=[u=c+dt→dt=dud]=bd2∫duu1/2+ad−bcd2∫duu3/2==2bd2u1/2−2(ad−bc)d2u−1/2==2(bu−ad+bc)d2u=2(bdt−ad+2bc)d2c+dt=nowputa=x,b=−y,c=x2+y2,d=−2xy,t=z=(xz−y)x2x2+y2−2xyz+C
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