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Question Number 79612 by john santu last updated on 26/Jan/20
∫dxx(x4+1)10=?
Answered by MJS last updated on 26/Jan/20
∫dxx12(x14+1)10=[t=x14→dx=4x34dt]=4∫t(t+1)10dt=4∫dt(t+1)9−4∫dt(t+1)10==−12(t+1)8+49(t+1)9=−9t+118(t+1)9==−9x14+118(x14+1)9+C
Commented by peter frank last updated on 26/Jan/20
thanks
Commented by john santu last updated on 27/Jan/20
thankyoumister
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