Question Number 80178 by Power last updated on 31/Jan/20
Commented by mr W last updated on 31/Jan/20
$${no}\:{exact}\:{value}\:{possible}! \\ $$$${x}^{\mathrm{25}} \underset{{k}=\mathrm{1}} {\overset{\mathrm{25}} {\prod}}\left(\mathrm{1}+\frac{\mathrm{1}}{\mathrm{3}^{{k}} }\right)=\mathrm{1} \\ $$$$\Rightarrow{x}=\frac{\mathrm{1}}{\sqrt[{\mathrm{25}}]{\underset{{k}=\mathrm{1}} {\overset{\mathrm{25}} {\prod}}\left(\mathrm{1}+\frac{\mathrm{1}}{\mathrm{3}^{{k}} }\right)}}\approx\mathrm{0}.\mathrm{982246} \\ $$
Commented by mr W last updated on 31/Jan/20
$${a}\:{new}\:{ID}\:{once}\:{again}? \\ $$
Commented by Power last updated on 31/Jan/20
$$\mathrm{what}? \\ $$
Commented by mr W last updated on 01/Feb/20
$${this}\:{question}\:{was}\:{once}\:{posted}\:{from} \\ $$$${somebody}\:{who}\:{changes}\:{his}\:{user}\:{ID}\: \\ $$$${frequently}.\:{now}\:{he}\:{has}\:{got}\:{a}\:{new}\:{ID} \\ $$$${once}\:{again}. \\ $$