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Question Number 80204 by jagoll last updated on 01/Feb/20

Commented by Tony Lin last updated on 01/Feb/20

$$28(x+y+z)=363+(x-z)$$$$ifx+y+z⩾14$$$$x-z⩾29>x+y+z\left(false\right)$$$$ifx+y+z=13$$$$thenx-z=1<x+y+z$$$$ifx+y+z⩽12$$$$z-x⩾27>x+y+z\left(false\right)$$$$therefore$$$$10x+10y+10z=130$$

Commented by jagoll last updated on 01/Feb/20

$$thankyousir$$

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