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Question Number 80296 by john santu last updated on 02/Feb/20

$$whatisthevalueof$$$$\underset{x\to -\mathrm{\infty }}{\lim }{e}^{\frac{6x^2+x}{3x+5}}?$$$$0or\mathrm{\infty }?$$

Commented by Tony Lin last updated on 02/Feb/20

$$lett=-x$$$$\underset{t\to +\mathrm{\infty }}{\lim }{e}^{\frac{6t^2-t}{5-3t}}$$$$=e^{\underset{t\to +\mathrm{\infty }}{\lim }\frac{6t^2-t}{5-3t}}$$$$\underset{t\to +\mathrm{\infty }}{\lim }\frac{6t^2-t}{5-3t}=\underset{t\to +\mathrm{\infty }}{\lim }\frac{12t-1}{-3}=-\mathrm{\infty }$$$$e^{-\mathrm{\infty }}=0$$

Commented by jagoll last updated on 02/Feb/20

Commented by jagoll last updated on 02/Feb/20

$$good$$

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