Math Question and Answers


Question and Answers Forum

All Questions Topic List
Integration Questions
Previous in All Question Next in All Question
Previous in Integration Next in Integration
Question Number 80300 by john santu last updated on 02/Feb/20

Commented by ~blr237~ last updated on 02/Feb/20

$\lim_{x \to - \infty} \frac{1}{x} = 0^{-} a n d \lim_{x \to 0^{-}} \frac{1}{x} = - \infty$ $\lim_{x \to 0^{-}} 3 x + 5 x^{2} = 0^{-} d u e t o t h e s i g n o f x (3 + 5 x) < 0 w h e n x \in] - \frac{3}{5}, 0 [s a m e l y w h e n x \to 0^{-}$ $s o t h e a n s \lim_{x \to - \infty} e^{\frac{6 x^{2} + x}{5 + 3 x}} = 0$
Commented by john santu last updated on 02/Feb/20

$w h a t w r o n g t h i s m e t h o d ? i s e e i n b o o k$ $c a l c u l u s 9^{t h} e d i t i o n b y P u r c e l l i k e$ $t h i s$
Commented by ~blr237~ last updated on 02/Feb/20

$m e a n t h a t t h e b o o k a s s u m e d t h a t y o u u n d e r s t o o d a l l t h e p a r t s i e x p l a i n$ $s e c o n d l y {d o n}^{'} t c o n t i n u e t o u s e (\frac{1}{0} = \infty) {i t}^{'} s n o t a p p r o p r i a t e$ $B u t \frac{1}{0^{+}} = + \infty a n d \frac{1}{0^{-}} = - \infty$ $x \to 0^{+} \Leftrightarrow x \in] 0, a [w i t h a \to 0$ $x \to 0^{-} \Leftrightarrow x \in] a, 0 [w i t h a \to 0$
Commented by MJS last updated on 02/Feb/20

$\frac{6 x^{2} + x}{3 x + 5} = 2 x - 3 + \frac{15}{3 x + 5}$ $\lim_{x \to - \infty} (2 x - 3) = - \infty; \lim_{x \to - \infty} \frac{15}{3 x + 5} = 0$ $\Rightarrow \lim_{x \to - \infty} \frac{6 x^{2} + x}{3 x + 5} = - \infty$ $\Rightarrow \lim_{x \to - \infty} e^{\frac{6 x^{2} + x}{3 x + 5}} = 0$
Terms of Service
Privacy Policy
Contact: info@tinkutara.com

Question and Answers Forum