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Question Number 8035 by Nayon last updated on 28/Sep/16

prove >> a^n +b^n =c^n   [n>2]  it has no integer roots

$${prove}\:>>\:{a}^{{n}} +{b}^{{n}} ={c}^{{n}} \:\:\left[{n}>\mathrm{2}\right] \\ $$ $${it}\:{has}\:{no}\:{integer}\:{roots} \\ $$ $$ \\ $$

Commented byFilupSmith last updated on 29/Sep/16

Do you mean:  Prove that  a^n +b^n ≠c^n     (∀n,a,b,c∈N:n>2)

$$\mathrm{Do}\:\mathrm{you}\:\mathrm{mean}: \\ $$ $$\mathrm{Prove}\:\mathrm{that}\:\:{a}^{{n}} +{b}^{{n}} \neq{c}^{{n}} \:\:\:\:\left(\forall{n},{a},{b},{c}\in\mathbb{N}:{n}>\mathrm{2}\right) \\ $$

Commented byjavawithfish last updated on 29/Sep/16

ask it to andrew wilze

$${ask}\:{it}\:{to}\:{andrew}\:{wilze} \\ $$

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