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Question Number 80386 by gny last updated on 02/Feb/20

Commented by kaivan.ahmadi last updated on 02/Feb/20

$$h_{A\stackrel{△}{BD}}=h_{A\stackrel{\mathrm{\Delta }}{BC}}=8\Rightarrow$$$$S_{A\stackrel{△}{BD}}=\frac{1}{2}\times 21\times 8=84$$$$S_{A\stackrel{\mathrm{\Delta }}{BC}}=\frac{1}{2}\times 12\times 8=48$$$$\Rightarrow S_{B\stackrel{\mathrm{\Delta }}{CD}}=S_{A\stackrel{\mathrm{\Delta }}{BD}}-S_{A\stackrel{\mathrm{\Delta }}{BC}}=84-48=36$$

Commented by gny last updated on 02/Feb/20

$$thankyousosomuchsir$$$$youarereallyperfect$$

Answered by sandy_delta last updated on 03/Feb/20

$$h_{BCD}=h_{ABC}=\sqrt{{10}^2-6^2}=8$$$$S_{BCD}=\frac{1}{2}\times 8\times 9=36$$

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