solve the D.E x^2 +(y^2 +1)dx+y(√(x^3 +1)) dy=0


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Question Number 80508 by M±th+et£s last updated on 03/Feb/20

$s o l v e t h e D . E$ $x^{2} + (y^{2} + 1) d x + y \sqrt{x^{3} + 1} d y = 0$
Commented by mr W last updated on 03/Feb/20

$s y n t a x o f e q u a t i o n i s w r o n g .$
Commented by M±th+et£s last updated on 03/Feb/20

$s o s o r r y b u t m y E n g l i s h {i s n}^{,} t g o o d$ $a n d i a m t r y i n g t o b e b e t t e r$
Commented by mr W last updated on 03/Feb/20

$y o u r e n g l i s h i s n o p r o b l e m s i r!$ $b u t t h e f o r m o f t h e e q u a t i o n$ $x^{2} + (y^{2} + 1) d x + y \sqrt{x^{3} + 1} d y = 0$ $m a k e s n o s e n s e .$ $e i t h e r y o u h a v e :$ $x^{2} + (y^{2} + 1) + y \sqrt{x^{3} + 1} \frac{d y}{d x} = 0$ $o r y o u h a v e :$ $[x^{2} + (y^{2} + 1)] d x + y \sqrt{x^{3} + 1} d y = 0$ $p l e a s e r e c h e c k!$
Commented by M±th+et£s last updated on 04/Feb/20

$y o u a r e r i g h t s i r i t s m y f a u l t i f o r g a t$ $t h e p a r e n t h e s e s$
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