((log_2 ^2 (x−4)−log_2 (4−x)^8 +16)/(30−3x−(4−x)^2 )) ≥ 0


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Question Number 80639 by jagoll last updated on 05/Feb/20

$\frac{\log_{2}^{2} (x - 4) - \log_{2} {(4 - x)}^{8} + 16}{30 - 3 x - {(4 - x)}^{2}} ⩾ 0$
Commented by john santu last updated on 05/Feb/20
$((log_2 ^2 (x−4)−8log_2 (x−4)+16)/(30−3x−16+8x−x^2 ))≥0 (1) x>4 (2)(({log_2 (x−4)−4}^2 )/(−x^2 +5x+14))≥0 (({log_2 (x−4)−4}^2 )/((x+2)(x−7)))≤0 ∴ 4<x<7 ∧x=20$
$\frac{\log_{2}^{2} (x - 4) - {8 \log}_{2} (x - 4) + 16}{30 - 3 x - 16 + 8 x - x^{2}} ⩾ 0$ $(1) x > 4$ $(2) \frac{{\log_{2} (x - 4) - 4}^{2}}{- x^{2} + 5 x + 14} ⩾ 0$ $\frac{{\log_{2} (x - 4) - 4}^{2}}{(x + 2) (x - 7)} ⩽ 0$ $∴ 4 < x < 7 \land x = 20$
Commented by jagoll last updated on 05/Feb/20

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