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Question Number 80739 by jagoll last updated on 05/Feb/20
cos3θ+2sin2θ=3¯θ∈(0,2π)whatisθ?
Commented by mr W last updated on 06/Feb/20
nosolution!becauseLHSmax=2<RJS!
Commented by hknkrc46 last updated on 06/Feb/20
sin2θ=1−cos2θcos3θ+2(1−cos2θ)=3cos3θ+2−2cos2θ=3cos3θ−2cos2θ=1cos2θ(cosθ−2)=1−1⩽cosθ⩽1⇒−3⩽cosθ−2⩽−1⇒cos2θ<0⇒θ∉(0,2π)
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