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Question Number 109005 by Study last updated on 20/Aug/20
ii=?
Answered by floor(10²Eta[1]) last updated on 20/Aug/20
i=eiπ2⇒ii=(eiπ2)i=e−π2
Answered by Dwaipayan Shikari last updated on 20/Aug/20
i2=eiπi=eiπ2ii=ei2π2=e−π2Orii=yilogi=logyi.iπ2=logyy=e−π2
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