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Question Number 81005 by mathocean1 last updated on 08/Feb/20
Answered by Rio Michael last updated on 09/Feb/20
$${V}_{{r}} \:=\mathrm{230}\:−\:\mathrm{180}\:=\:\mathrm{50}\:{V} \\ $$$${R}_{{t}} \:=\:\frac{\mathrm{5}{r}}{\mathrm{5}\:+{r}} \\ $$$${from}\:{the}\:{max}\:{power}\:{theorem},{r}\:=\:{R} \\ $$$$\Rightarrow\:{r}\:=\:\mathrm{5}\:\Omega \\ $$$${I}_{\mathrm{1}} \:=\:\frac{{V}_{{r}} }{{R}_{{t}} \:}\:=\:\mathrm{20}{A} \\ $$$${I}_{\mathrm{2}} =\:\frac{{V}}{{R}_{{t}\mathrm{2}} \:}\:=\:\mathrm{48}{A}\:\left({approx}\right) \\ $$$${I}\:=\:{I}_{\mathrm{1}} \:+\:{I}_{\mathrm{2}} \:=\:\mathrm{68}{A} \\ $$
Commented by mathocean1 last updated on 12/Feb/20
$${please}\:{sirs}\:{what}\:{means}\:{approx}\:? \\ $$
Commented by Rio Michael last updated on 12/Feb/20
$${approximately} \\ $$