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Question Number 81008 by M±th+et£s last updated on 08/Feb/20

Commented by jagoll last updated on 09/Feb/20

$$\left(2\right)a\sin t+b\cos t=\sqrt{a^2+b^2}\cos (t-\alpha )$$$$where\alpha ={\tan }^{-1}\left(\frac{a}{b}\right)$$$$maxvalue=\sqrt{a^2+b^2}$$$$minvalue=-\sqrt{a^2+b^2}$$

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