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Question Number 81092 by ahmadshahhimat775@gmail.com last updated on 09/Feb/20

Commented by john santu last updated on 09/Feb/20

do you mean lim_(n→∞)  ((ln(n))/2^n ) ?

$${do}\:{you}\:{mean}\:\underset{{n}\rightarrow\infty} {\mathrm{lim}}\:\frac{{ln}\left({n}\right)}{\mathrm{2}^{{n}} }\:? \\ $$

Commented by msup trace by abdo last updated on 09/Feb/20

x→2^x   increase more than  x→ln(x) ⇒lim_(n→+∞)   ((ln(n))/2^n )=0

$${x}\rightarrow\mathrm{2}^{{x}} \:\:{increase}\:{more}\:{than} \\ $$$${x}\rightarrow{ln}\left({x}\right)\:\Rightarrow{lim}_{{n}\rightarrow+\infty} \:\:\frac{{ln}\left({n}\right)}{\mathrm{2}^{{n}} }=\mathrm{0} \\ $$

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