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Question Number 81133 by 1406 last updated on 09/Feb/20

find this   ∫(1/(sin^2 x((cot^4 x))^(1/7) ))dx

$${find}\:{this}\: \\ $$$$\int\frac{\mathrm{1}}{{sin}^{\mathrm{2}} {x}\sqrt[{\mathrm{7}}]{{cot}^{\mathrm{4}} {x}}}{dx} \\ $$

Commented by jagoll last updated on 10/Feb/20

∫ ((csc^2 x dx)/((cot^4 x))^(1/(7 )) ) = −∫((  d(cot x))/(cot^(4/7) x)) =  − ∫ u^(−(4/7))  du = −(7/3) ((cot^3 x))^(1/(7 ))  +c

$$\int\:\frac{{csc}^{\mathrm{2}} {x}\:{dx}}{\sqrt[{\mathrm{7}\:}]{\mathrm{cot}\:^{\mathrm{4}} {x}}}\:=\:−\int\frac{\:\:{d}\left(\mathrm{cot}\:{x}\right)}{\mathrm{cot}\:^{\frac{\mathrm{4}}{\mathrm{7}}} {x}}\:= \\ $$$$−\:\int\:{u}^{−\frac{\mathrm{4}}{\mathrm{7}}} \:{du}\:=\:−\frac{\mathrm{7}}{\mathrm{3}}\:\sqrt[{\mathrm{7}\:}]{\mathrm{cot}\:^{\mathrm{3}} {x}}\:+{c}\: \\ $$

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