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Question Number 81403 by naka3546 last updated on 12/Feb/20

$$Solvex\in \mathbb{R}suchthat$$$$\frac{{(x+1)}^5}{(x^5+1)}=\frac{81}{11}$$

Commented by MJS last updated on 12/Feb/20

$$x\ne -1$$$$(x+1)(x-\frac{1}{2})(x-2)(x^2+\frac{5}{7}x+1)=0$$$$x_1=\frac{1}{2}$$$$x_2=2$$$$x_{3,4}=-\frac{5}{14}\pm \frac{3\sqrt{19}}{14}\mathrm{i}$$

Answered by ajfour last updated on 12/Feb/20

$$\frac{x^4-x^3+x^2-x+1}{{(x+1)}^4}=\frac{11}{81}$$$$x=2.$$

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