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Question Number 81649 by Power last updated on 14/Feb/20

Commented by Power last updated on 14/Feb/20

$$\mathrm{BDM}\mathrm{triangular}\mathrm{face}-?$$

Commented by Power last updated on 14/Feb/20

$$\mathrm{AD}=17$$

Commented by key of knowledge last updated on 14/Feb/20

$$\mathrm{BC}\mid \mid \mathrm{AD}?$$

Commented by Power last updated on 14/Feb/20

$$\mathrm{BC}\mid \mid \mathrm{AD},\mathrm{AB}=\mathrm{BD}$$

Commented by Power last updated on 14/Feb/20

$$\mathrm{AB}=\mathrm{CD}$$

Commented by Power last updated on 14/Feb/20

$$\mathrm{AB}=\mathrm{BD}\mathrm{no}\mathrm{correct}!$$

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