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Question Number 81821 by ahmadshahhimat775@gmail.com last updated on 15/Feb/20

	Answered by TANMAY PANACEA last updated on 15/Feb/20

	$1899 = 3 \times 633$ $= 3 \times 3 \times 211 = 3^{2} \times {(211)}^{1}$ $n u m b e r o f d e v i s o r = (2 + 1) (1 + 1) = 6$ $f o r m u l a N = a^{p} \times b^{q} \times c^{r}$ $n u b e r o f d e v i s o r n = (p + 1) (q + 1) (r + 1)$ $n u m b e r o f d e v i s o r$ $3, 9, 633, 1899, 211, 1$ $p l s c h e c k . . .$
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