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Question Number 81884 by rajesh4661kumar@gmail.com last updated on 16/Feb/20
Commented by mind is power last updated on 16/Feb/20
appliewecanfindtrianglewithesin−x,sin−y,sin−zanglewitheoriantationa+b+c=π⇒sin(a)cos(a)+sin(b)cos(b)+sin(c)cos(c)=2sin(a)sin(b)sin(c)..1?⇒sin(2a)+sin(2b)+sin(2c)=4sin(a)sin(b)sin(c)..2sin(2a)+sin(2b)=2cos(a−b)sin(a+b)sin(2c)=sin(2π−2a−2b)=−sin(2a+2b)=−2sin(a+b)cos(a+b)sin(2a)+sin(2b)+sin(2c)=2cos(a−b)sin(a+b)−2sin(a+b)cos(a+b)=2sin(a+b)(cos(a−b)−cos(a+b))=4sin(a)sin(b)sin(π−c)=4sin(a)sin(b)sin(c)2..proved⇔1Truefora=sin−(x),b=sin−(y),sin−(z)=csin(a)=x,cos(a)=1−x2......⇒1⇔x1−x2+y1−y2+z1−z2=2xyz
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