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Question Number 81910 by mr W last updated on 16/Feb/20
a1=1a2=2an+1=(n+1)an−2an−1findan=?
Commented by jagoll last updated on 16/Feb/20
a3=3a2−2a1=6−2=4a4=4a3−2a2=16−4=12a5=5a4−2a3=60−8=52a6=6a5−2a4=312−24=288
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