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Question Number 81910 by mr W last updated on 16/Feb/20

a_1 =1  a_2 =2  a_(n+1) =(n+1)a_n −2a_(n−1)   find a_n =?

a1=1a2=2an+1=(n+1)an2an1findan=?

Commented by jagoll last updated on 16/Feb/20

a_3  = 3a_2 −2a_1  = 6−2=4  a_(4 ) = 4a_3 −2a_2  = 16−4=12  a_5  = 5a_4 −2a_3  = 60 − 8=52  a_6  = 6a_5  − 2a_4  = 312−24=288

a3=3a22a1=62=4a4=4a32a2=164=12a5=5a42a3=608=52a6=6a52a4=31224=288

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