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Question Number 81927 by zainal tanjung last updated on 16/Feb/20

$$\mathrm{One}\mathrm{man}\mathrm{adds}3\mathrm{litres}\mathrm{of}\mathrm{water}\mathrm{to}12\mathrm{litres}\mathrm{of}\mathrm{milk}$$$$\mathrm{and}\mathrm{another}4\mathrm{litres}\mathrm{of}\mathrm{water}\mathrm{to}10\mathrm{litres}\mathrm{of}\mathrm{milk}.$$$$\mathrm{What}\mathrm{is}\mathrm{the}\mathrm{ratio}\mathrm{of}\mathrm{the}\mathrm{strengths}\mathrm{of}\mathrm{milk}\mathrm{in}\mathrm{the}$$$$\mathrm{two}\mathrm{mixtures}?$$

Answered by TANMAY PANACEA last updated on 16/Feb/20

$${(water+milk)}_{first}=3+12=15$$$$\mathrm{\%}milk=\frac{12}{15}\times 100=\frac{4}{5}\times 100=80$$$${(water+milk)}_{second}=4+10=14$$$$\mathrm{\%}milk=\frac{10}{14}\times 100=71.43$$

Answered by MJS last updated on 16/Feb/20

$$\mathrm{mixture}1\mathrm{contains}\frac{12}{3+12}=\frac{4}{5}\mathrm{milk}$$$$\mathrm{mixture}2\mathrm{contains}\frac{10}{4+10}=\frac{5}{7}\mathrm{milk}$$$$\frac{\mathrm{mixture}1}{\mathrm{mixture}2}=\frac{28}{25}\Rightarrow \mathrm{ratio}\mathrm{is}28:25$$

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