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Question Number 81942 by TawaTawa last updated on 16/Feb/20

	Answered by TANMAY PANACEA last updated on 16/Feb/20

	$f o r b a n k p i n t e r e s t = \frac{3000 \times 1 \times x}{100} = 30 x$ $f o r b a n k Q i n t e r s t = \frac{2000 \times 1 \times y}{100} = 20 y$ $a s p e r s e c o n d c o n d i t i o n$ $i n t e r e s t i n b a n k p = \frac{2000 \times 1 \times x}{100} = 20 x$ $i n t e r s t i n b a n k Q = \frac{3000 \times 1 \times y}{100} = 30 y$ $(20 x + 30 y) - (30 x + 20 y) = 20$ $10 y - 10 x = 20$ $y - x = 2$ $d a t a i n s u f f i c i e n t$
	Commented by TawaTawa last updated on 16/Feb/20

	$God bless you sir .$
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