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Question Number 81971 by TawaTawa last updated on 17/Feb/20

Answered by mind is power last updated on 17/Feb/20

$$anglebetweenWireandvertical={\cos }^{-1}\left(\frac{1.5}{2}\right)=\alpha$$$$weget\mathrm{\Sigma }\overrightarrow{F}=\overrightarrow{0}$$$$\Rightarrow {\overrightarrow{T}}_{1y}+{\overrightarrow{T}}_{2y}+{\overrightarrow{T}}_{3y}=P=m\overrightarrow{g}$$$$T_{1y}=T_{2y}=T_{3y}=Tcos\left(\alpha \right)$$$$\Rightarrow 3Tcos\left(\alpha \right)=mg$$$$T=\frac{mg}{3cos\left(\alpha \right)}=\frac{44.9.81}{3.\frac{1.5}{2}}=\frac{176.9.81}{9}=(1.09).176)\sim 193,6N$$

Commented by TawaTawa last updated on 17/Feb/20

$$\mathrm{God}\mathrm{bless}\mathrm{you}\mathrm{sir}$$

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