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Question Number 82019 by M±th+et£s last updated on 17/Feb/20

Answered by mind is power last updated on 18/Feb/20

2F1(k+1,k+1;k+2;1)=(k+1)∫_0 ^1 x^k (1−x)^(−k−1) dx  not defind sir tchek this Quation

$$\mathrm{2}{F}\mathrm{1}\left({k}+\mathrm{1},{k}+\mathrm{1};{k}+\mathrm{2};\mathrm{1}\right)=\left({k}+\mathrm{1}\right)\int_{\mathrm{0}} ^{\mathrm{1}} {x}^{{k}} \left(\mathrm{1}−{x}\right)^{−{k}−\mathrm{1}} {dx} \\ $$$${not}\:{defind}\:{sir}\:{tchek}\:{this}\:{Quation} \\ $$

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