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Question Number 82111 by john santu last updated on 18/Feb/20

a word is formed with 3 vowels  and 3 consonants without   repetition . the probability the  formation of words begining the  letter z is?

awordisformedwith3vowelsand3consonantswithoutrepetition.theprobabilitytheformationofwordsbeginingtheletterzis?

Commented by john santu last updated on 18/Feb/20

i′ got answer p = (C_2 ^(20) /(6×C_3 ^( 21) ))

igotanswerp=C2206×C321

Commented by mr W last updated on 18/Feb/20

p=((C_2 ^(20) C_3 ^5 5!)/(C_3 ^(21) C_3 ^5 6!))=(C_2 ^(20) /(6C_3 ^(21) ))=(1/(42))

p=C220C355!C321C356!=C2206C321=142

Commented by jagoll last updated on 18/Feb/20

n(S) = 6! C _3^(21) .C_3 ^5   n(A) = 5! C_2 ^(20) .C_3 ^5   p(A) = ((5! C_2 ^(21) .C_3 ^5 )/(6! C_3 ^(21) .C_3 ^5 )) = (C_2 ^(21) /(6.C_3 ^(21) ))

n(S)=6!C321.C35n(A)=5!C220.C35p(A)=5!C221.C356!C321.C35=C2216.C321

Commented by mr W last updated on 18/Feb/20

6 is correct sir!

6iscorrectsir!

Commented by jagoll last updated on 18/Feb/20

thank you sir

thankyousir

Commented by john santu last updated on 18/Feb/20

thank you. i wrote it wrong  because  in a hurry

thankyou.iwroteitwrongbecauseinahurry

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