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Question Number 82176 by oyemi kemewari last updated on 19/Feb/20

Commented by jagoll last updated on 19/Feb/20

(1b) (√(32−2(√(135)))) = (√(27+5−2(√(27×5))))  = (√(27))−(√5) = 3(√3)−(√5)

(1b)322135=27+5227×5=275=335

Commented by jagoll last updated on 19/Feb/20

(2b) α×(α+3) = 28  α^2 +3α−28=0  (α+7)(α−4)=0  (i) k = 2α+3 = −11  (ii) k = 2α+3 = 11

(2b)α×(α+3)=28α2+3α28=0(α+7)(α4)=0(i)k=2α+3=11(ii)k=2α+3=11

Commented by john santu last updated on 19/Feb/20

((cos x)/(1+sin x)) + ((1+sin x)/(cos x)) =   ((cos^2 x+1+2sin x+sin^2 x)/(cos x(1+sin x))) =?  ((2(1+sin x))/(cos x(1+sin x))) = (2/(cos x)) = 2sec x

cosx1+sinx+1+sinxcosx=cos2x+1+2sinx+sin2xcosx(1+sinx)=?2(1+sinx)cosx(1+sinx)=2cosx=2secx

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