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Question Number 82392 by naka3546 last updated on 21/Feb/20

Commented by naka3546 last updated on 21/Feb/20

$$Areaofshadedregionis...$$

Commented by mr W last updated on 21/Feb/20

$$shadedarea=\frac{\pi R^2}{4}-\pi r^2=\frac{\pi (R^2-{\left(2r\right)}^2)}{4}$$$$=\frac{\pi \times {12}^2}{4}=36\pi$$

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