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Question Number 82476 by abdomathmax last updated on 21/Feb/20
solvexy″+2y′+xy=0withinitialconditionsy(o)=1andy′(1)=0
Answered by mind is power last updated on 21/Feb/20
z=xy⇒z′=y+xy′z″=2y′+xy″xy″+2y′+xy=0⇒z″+z=0
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