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Question Number 82593 by Power last updated on 22/Feb/20

Commented by mr W last updated on 23/Feb/20

t=(√x)>0 t^4 −16t−12=0 (t^2 −2t−2)(t^2 +2t+6)=0 t^2 +2t+6=(t+1)^2 +5>0 t^2 −2t−2=0 ⇒t^2 −2t=2=x−2(√x) if x∈C: t=−1±(√5)i x−2(√x)=t^2 −2t=t^2 +2t−4t =−6−4t =−6−4(−1±(√5)i) =−2±4(√5)i

t=x>0t4−16t−12=0(t2−2t−2)(t2+2t+6)=0t2+2t+6=(t+1)2+5>0t2−2t−2=0⇒t2−2t=2=x−2xifx∈C:t=−1±5ix−2x=t2−2t=t2+2t−4t=−6−4t=−6−4(−1±5i)=−2±45i

Commented by peter frank last updated on 23/Feb/20

mr w please help 82596

mrwpleasehelp82596

Commented by Power last updated on 23/Feb/20

thank you sir

thankyousir

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