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Question Number 82607 by arthur.kangdani@gmail.com last updated on 23/Feb/20

Commented by jagoll last updated on 23/Feb/20

lim_(x→2) ((4−x^2 )/(4−x^2 )) × lim_(x→2) 3+(√(x^2 +5)) = 1×6 = 6

$$\underset{{x}\rightarrow\mathrm{2}} {\mathrm{lim}}\:\frac{\mathrm{4}−{x}^{\mathrm{2}} }{\mathrm{4}−{x}^{\mathrm{2}} }\:×\:\underset{{x}\rightarrow\mathrm{2}} {\mathrm{lim}}\:\mathrm{3}+\sqrt{{x}^{\mathrm{2}} +\mathrm{5}}\:=\:\mathrm{1}×\mathrm{6}\:=\:\mathrm{6} \\ $$

Commented by niroj last updated on 23/Feb/20

yes my friend your saying true. its been error by the wrong lim now done.

$$\:\mathrm{yes}\:\mathrm{my}\:\mathrm{friend}\:\mathrm{your}\:\mathrm{saying}\:\mathrm{true}. \\ $$$$\:\mathrm{its}\:\mathrm{been}\:\mathrm{error}\:\mathrm{by}\:\mathrm{the}\:\mathrm{wrong}\:\mathrm{lim}\: \\ $$$$\:\mathrm{now}\:\mathrm{done}. \\ $$

Commented by jagoll last updated on 23/Feb/20

not correct . how you got 2(√(2^2 +5 )) = 2(√(14 )) ?

$${not}\:{correct}\:.\:{how}\:{you}\:{got} \\ $$$$\mathrm{2}\sqrt{\mathrm{2}^{\mathrm{2}} +\mathrm{5}\:}\:=\:\mathrm{2}\sqrt{\mathrm{14}\:}\:? \\ $$

Commented by jagoll last updated on 23/Feb/20

this equation lim_(x→2) not lim_(x→3)

$${this}\:{equation}\:\underset{{x}\rightarrow\mathrm{2}} {\mathrm{lim}}\:{not}\:\underset{{x}\rightarrow\mathrm{3}} {\mathrm{lim}}\: \\ $$

Commented by mathmax by abdo last updated on 23/Feb/20

=lim_(x→2) (((4−x^2 )(3+(√(x^2 +5))))/(9−x^2 −5))=lim_(x→2) (((4−x^2 )(3+(√(x^2 +5))))/(4−x^2 )) =lim_(x→2) (3+(√(x^2 +5))) =6

$$={lim}_{{x}\rightarrow\mathrm{2}} \:\:\:\frac{\left(\mathrm{4}−{x}^{\mathrm{2}} \right)\left(\mathrm{3}+\sqrt{{x}^{\mathrm{2}} \:+\mathrm{5}}\right)}{\mathrm{9}−{x}^{\mathrm{2}} −\mathrm{5}}={lim}_{{x}\rightarrow\mathrm{2}} \:\:\frac{\left(\mathrm{4}−{x}^{\mathrm{2}} \right)\left(\mathrm{3}+\sqrt{{x}^{\mathrm{2}} +\mathrm{5}}\right)}{\mathrm{4}−{x}^{\mathrm{2}} } \\ $$$$={lim}_{{x}\rightarrow\mathrm{2}} \:\:\left(\mathrm{3}+\sqrt{{x}^{\mathrm{2}} +\mathrm{5}}\right)\:=\mathrm{6} \\ $$

Answered by niroj last updated on 23/Feb/20

_(x→2) ^(lim) ((4−x^2 )/(3−(√(x^2 +5)))) = _(x→2) ^(lim) ((−2x)/((−2x)/(2(√(x^2 +5))))) = _(x→2) ^(lim) 2(√(x^2 +5)) = 2 (√(2^2 +5)) =2(√9)=2.3=6//.

$$ \\ $$$$\:\: \\ $$$$\:\underset{\mathrm{x}\rightarrow\mathrm{2}} {\overset{\mathrm{lim}} {\:}}\:\frac{\mathrm{4}−\mathrm{x}^{\mathrm{2}} }{\mathrm{3}−\sqrt{\mathrm{x}^{\mathrm{2}} +\mathrm{5}}} \\ $$$$\:=\underset{\mathrm{x}\rightarrow\mathrm{2}} {\overset{\mathrm{lim}} {\:}}\:\:\frac{−\mathrm{2x}}{\frac{−\mathrm{2x}}{\mathrm{2}\sqrt{\mathrm{x}^{\mathrm{2}} +\mathrm{5}}}}\:=\underset{\mathrm{x}\rightarrow\mathrm{2}} {\overset{\mathrm{lim}} {\:}}\:\mathrm{2}\sqrt{\mathrm{x}^{\mathrm{2}} +\mathrm{5}} \\ $$$$=\:\mathrm{2}\:\sqrt{\mathrm{2}^{\mathrm{2}} +\mathrm{5}}\:\:=\mathrm{2}\sqrt{\mathrm{9}}=\mathrm{2}.\mathrm{3}=\mathrm{6}//. \\ $$

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