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Question Number 8262 by 666225 last updated on 04/Oct/16

∣x−1∣ < 2 ⇒ ∣x−3∣

∣x−1∣<2⇒∣x−3∣

Commented by123456 last updated on 04/Oct/16

∣x−1∣<2⇔−2<x−1<2 −2−2<x−3<2−2 −4<x−3<0 0<∣x−3∣<4

∣x−1∣<2⇔−2<x−1<2 −2−2<x−3<2−2 −4<x−3<0 0<∣x−3∣<4

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