Question Number 8269 by tawakalitu last updated on 04/Oct/16
Commented by tawakalitu last updated on 04/Oct/16
$$\mathrm{Find}\:\mathrm{x}\:\mathrm{and}\:\mathrm{y}.\:\mathrm{thanks}\:\mathrm{in}\:\mathrm{advance}. \\ $$
Answered by prakash jain last updated on 05/Oct/16
$${x}+{y}=\sqrt{\mathrm{2}}\mathrm{cos}\:\mathrm{45}=\sqrt{\mathrm{2}}×\frac{\mathrm{1}}{\sqrt{\mathrm{2}}}=\mathrm{1} \\ $$$$\mathrm{Perpendicular}\:\mathrm{line}\:\mathrm{on}\:\mathrm{right}\:\mathrm{side} \\ $$$${x}\mathrm{tan}\:\mathrm{60}=\sqrt{\mathrm{2}}\mathrm{sin}\:\mathrm{45}\Rightarrow{x}=\frac{\mathrm{1}}{\mathrm{tan}\:\mathrm{60}}=\frac{\mathrm{1}}{\sqrt{\mathrm{3}}} \\ $$$${y}=\mathrm{1}−\frac{\mathrm{1}}{\sqrt{\mathrm{3}}}=\frac{\sqrt{\mathrm{3}}−\mathrm{1}}{\sqrt{\mathrm{3}}} \\ $$
Commented by tawakalitu last updated on 05/Oct/16
$$\mathrm{Thanks}\:\mathrm{for}\:\mathrm{your}\:\mathrm{help}. \\ $$