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Question Number 82878 by mr W last updated on 25/Feb/20

Commented by behi83417@gmail.com last updated on 25/Feb/20

Beautiful quistion.waiting for answer...

Beautifulquistion.waitingforanswer...

Commented by ajfour last updated on 25/Feb/20

so please answer Behi Sir..

sopleaseanswerBehiSir..

Commented by behi83417@gmail.com last updated on 25/Feb/20

dear Ajfour sir! i am waiting for answer  of my master: mrW.(also your answer  too,most welcome.)

dearAjfoursir!iamwaitingforanswerofmymaster:mrW.(alsoyouranswertoo,mostwelcome.)

Answered by mr W last updated on 26/Feb/20

Commented by mr W last updated on 26/Feb/20

ΔAFG:  semi perimeter=u  incircle radius =n  excircle radius =a  u=((p+q+s)/2)  n=(Δ_(AFG) /u)  ⇒(1/n)=(u/Δ_(AFG) )  a=(Δ_(AFG) /(u−s))  ⇒(1/a)=((u−s)/Δ_(AFG) )    ΔAGE:  semi perimeter=v  incircle radius =b  excircle radius =m  v=((q+r+t)/2)  similarly  ⇒(1/b)=(v/Δ_(AGE) )  ⇒(1/m)=((v−t)/Δ_(AGE) )    (1/a)+(1/b)=((u−s)/Δ_(AFG) )+(v/Δ_(AGE) )=(1/Δ_(AFG) )(u−s+(Δ_(AFG) /Δ_(AGE) )v)  ⇒(1/a)+(1/b)=(1/Δ_(AFG) )(u−s+(s/t)v)  (1/n)+(1/m)=(u/Δ_(AFG) )+((v−t)/Δ_(AGE) )=(1/Δ_(AFG) )[u+(Δ_(AFG) /Δ_(AGE) )(v−t)]  (1/n)+(1/m)=(1/Δ_(AFG) )[u+(s/t)(v−t)]  ⇒(1/n)+(1/m)=(1/Δ_(AFG) )(u+(s/t)v−s)  ⇒(1/a)+(1/b)=(1/m)+(1/n)

ΔAFG:semiperimeter=uincircleradius=nexcircleradius=au=p+q+s2n=ΔAFGu1n=uΔAFGa=ΔAFGus1a=usΔAFGΔAGE:semiperimeter=vincircleradius=bexcircleradius=mv=q+r+t2similarly1b=vΔAGE1m=vtΔAGE1a+1b=usΔAFG+vΔAGE=1ΔAFG(us+ΔAFGΔAGEv)1a+1b=1ΔAFG(us+stv)1n+1m=uΔAFG+vtΔAGE=1ΔAFG[u+ΔAFGΔAGE(vt)]1n+1m=1ΔAFG[u+st(vt)]1n+1m=1ΔAFG(u+stvs)1a+1b=1m+1n

Commented by ajfour last updated on 28/Feb/20

Thanks sir, what a presentation!

Thankssir,whatapresentation!

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