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Question Number 82995 by M±th+et£s last updated on 26/Feb/20

Commented by mr W last updated on 26/Feb/20

a_(1000) =(1/(499501)) ?

a1000=1499501?

Answered by mind is power last updated on 26/Feb/20

⇒(1/a_(n+1) )=n+(1/a_n )  let b_n =(1/a_n )  ⇒b_(n+1) =n+b_n   b_0 =1  ⇒Σ_(k=0) ^(n−1) (b_(k+1) −b_k )=Σ_(k=0) ^(n−1) k  ⇒b_n −b_0 =(n/2)(n−1)  ⇒b_n =1+(n/2)(n−1)  ⇒a_n =(1/b_n )=(2/(n^2 −n+2))  a_(1000) =(2/(999002))=(1/(499501))

1an+1=n+1anletbn=1anbn+1=n+bnb0=1n1k=0(bk+1bk)=n1k=0kbnb0=n2(n1)bn=1+n2(n1)an=1bn=2n2n+2a1000=2999002=1499501

Commented by mr W last updated on 26/Feb/20

fine sir! i got the same.

finesir!igotthesame.

Commented by M±th+et£s last updated on 26/Feb/20

thank you sir.this is the value

thankyousir.thisisthevalue

Commented by mind is power last updated on 27/Feb/20

withe pleasur

withepleasur

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