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Question Number 83115 by 09658867628 last updated on 28/Feb/20

∫cos xe^(sin x) dx

$$\int\mathrm{cos}\:{xe}^{\mathrm{sin}\:{x}} {dx} \\ $$

Commented by niroj last updated on 28/Feb/20

   ∫cos x e^(sin x) dx    ∫ e^(sin x)  cos x dx    Put sin x= t         cos xdx=dt     ∫ e^t . dt= e^t  +C     e^(sin x) +C //

$$ \\ $$$$\:\int\boldsymbol{\mathrm{cos}}\:\boldsymbol{\mathrm{x}}\:\boldsymbol{\mathrm{e}}^{\boldsymbol{\mathrm{sin}}\:\boldsymbol{\mathrm{x}}} \boldsymbol{\mathrm{dx}} \\ $$$$\:\:\int\:\mathrm{e}^{\mathrm{sin}\:\mathrm{x}} \:\mathrm{cos}\:\mathrm{x}\:\mathrm{dx} \\ $$$$\:\:\mathrm{Put}\:\mathrm{sin}\:\mathrm{x}=\:\mathrm{t} \\ $$$$\:\:\:\:\:\:\:\mathrm{cos}\:\mathrm{xdx}=\mathrm{dt} \\ $$$$\:\:\:\int\:\mathrm{e}^{\mathrm{t}} .\:\mathrm{dt}=\:\mathrm{e}^{\mathrm{t}} \:+\mathrm{C} \\ $$$$\:\:\:\mathrm{e}^{\mathrm{sin}\:\mathrm{x}} +\mathrm{C}\:// \\ $$

Answered by som(math1967) last updated on 28/Feb/20

∫e^(sinx) d(sinx)=e^(sinx) +C

$$\int{e}^{{sinx}} {d}\left({sinx}\right)={e}^{{sinx}} +{C} \\ $$

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