y=x^(4ln x)


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Question Number 83131 by 09658867628 last updated on 28/Feb/20

$y = x^{4 \ln x}$
Commented by mr W last updated on 28/Feb/20

$d e a r s i r :$ $p l e a s e s t o p p o s t i n g t h e s a m e q u e s t i o n s$ $m o r e t i m e s! i f i t o c c u r s b y m i s t a k e,$ $y o u c a n d e l e t e t h e p o s t s w h i c h a r e$ $t o o m u c h$ $b e s i d e s p l e a s e m a k e c l e a r w h a t y o u$ $r e q u e s t w i t h y o u r q u e s t i o n s!$
Commented by mr W last updated on 28/Feb/20

$s i r :$ $y o u a r e s t i l l p o s t i n g a l o t o f ‘ ‘ {q u e s t i o n s}^{″}$ $w i t h o u t t e l l i n g w h a t y o u r q u e s t i o n$ $i s . t h i s i s b o r i n g a n d a l s o r e s p e c t l e s s$ $t o o t h e r u s e r s . c a n y o u p l e a s e r e f r a i n$ $t h i s ? t h a n k y o u!$
Commented by 20092104 last updated on 04/Mar/20

$y = x^{4 \ln x}$ $\ln y = 4 \ln x \ln x$ $\ln y = 4 {(\ln x)}^{2}$ $\frac{y^{'}}{y} = 4 \cdot 2 \ln x \cdot \frac{1}{x}$ $y^{'} = x^{4 \ln x} \frac{8 \ln x}{x}$
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