Question Number 83139 by ~blr237~ last updated on 28/Feb/20
$${let}\:\:\:{c}_{\mathrm{0}} \:>\mathrm{0}\:\:{and}\:\:\forall\:{n}\in\mathbb{N}\:\:{c}_{{n}+\mathrm{1}} =\sqrt{\frac{\mathrm{1}}{\mathrm{2}}\left({c}_{{n}} +\frac{\mathrm{1}}{{c}_{{n}} }\:\right)\:}\:\:\: \\ $$ $${Explicit}\:\:{c}_{{n}} \:{in}\:{term}\:{of}\:{n}\:{and}\:\:{c}_{\mathrm{0}} \:\: \\ $$