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Question Number 83213 by ~blr237~ last updated on 28/Feb/20

$$Provethat\mathrm{\forall }\theta \in \mathbb{R}\underset{n=1}{\sum ^{\mathrm{\infty }}}{3}^{n-1}{sin}^3\left(\frac{\theta }{3^n}\right)=\frac{\theta -sin\theta }{4}$$

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