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Question Number 83307 by ajfour last updated on 29/Feb/20

Commented by mr W last updated on 01/Mar/20

$$atequilibriumpositionhalfofthe$$$$objectissubmerged,therefore$$$$\rho =\frac{1}{2}{\rho }_0$$

Commented by ajfour last updated on 29/Feb/20

$$\mathrm{If}\mathrm{a}\mathrm{cuboidal}\mathrm{piece}\mathrm{of}\mathrm{wood},$$$$\mathrm{released}\mathrm{over}\mathrm{the}\mathrm{surface}\mathrm{of}\mathrm{a}$$$$\mathrm{large}\mathrm{tank}\mathrm{just}\mathrm{submerges}$$$$\mathrm{completely}\mathrm{and}\mathrm{then}\mathrm{starts}$$$$\mathrm{rising}\mathrm{up}\mathrm{again},\mathrm{and}\mathrm{oscillates}$$$$\mathrm{in}\mathrm{this}\mathrm{manner},\mathrm{find}\mathrm{its}\mathrm{density}\rho .$$$$\left(\mathrm{given}\mathrm{density}\mathrm{of}\mathrm{water}\mathrm{is}{\rho }_0\right)$$

Commented by mr W last updated on 29/Feb/20

Commented by ajfour last updated on 01/Mar/20

$$YesSir,thanks,quitestraight!$$

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