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Question Number 83381 by Rio Michael last updated on 01/Mar/20

$$\mathrm{Given}\mathrm{that}\mathrm{the}\mathrm{function}f\left(x\right)=x^3\mathrm{is}$$$$\mathrm{differentiable}\mathrm{in}\mathrm{the}\mathrm{interval}(-2,2)\mathrm{us}\mathrm{the}\mathrm{mean}$$$$\mathrm{value}\mathrm{theorem}\mathrm{to}\mathrm{find}\mathrm{the}\mathrm{value}\mathrm{of}x\mathrm{for}\mathrm{which}\mathrm{the}$$$$\mathrm{tangent}\mathrm{to}\mathrm{the}\mathrm{curve}\mathrm{is}\mathrm{parrallel}\mathrm{to}\mathrm{the}\mathrm{chord}$$$$\mathrm{through}\mathrm{the}\mathrm{points}(-2,8)\mathrm{and}(2,8).$$

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