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Question Number 83403 by jagoll last updated on 02/Mar/20

$$\mathrm{what}\mathrm{is}\mathrm{range}\mathrm{function}$$$$\mathrm{y}=\frac{1}{{(\mathrm{x}-1)}^2}$$

Answered by MJS last updated on 02/Mar/20

$$y=\frac{1}{{(x-1)}^2}\mathrm{defined}\mathrm{for}x\ne 1$$$$x=1\pm \frac{1}{\sqrt{y}}\mathrm{defined}\mathrm{for}y>0=\mathrm{range}$$

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