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Question Number 83481 by gny last updated on 02/Mar/20

Commented by gny last updated on 02/Mar/20

sir could you help me           Find  α+β

$${sir}\:{could}\:{you}\:{help}\:{me}\:\:\:\:\:\:\:\:\:\:\:{Find}\:\:\alpha+\beta \\ $$

Commented by mathmax by abdo last updated on 02/Mar/20

α+10 +β+20 =180 ⇒α+β =180−30 =150^o

$$\alpha+\mathrm{10}\:+\beta+\mathrm{20}\:=\mathrm{180}\:\Rightarrow\alpha+\beta\:=\mathrm{180}−\mathrm{30}\:=\mathrm{150}^{{o}} \\ $$

Commented by gny last updated on 03/Mar/20

thank you sir

$${thank}\:{you}\:{sir} \\ $$

Answered by Rio Michael last updated on 04/Mar/20

(β + 20)°+( α + 10)° = 180°  ⇒ α + β = 180 °− 20° − 10 °        α + β = 150°

$$\left(\beta\:+\:\mathrm{20}\right)°+\left(\:\alpha\:+\:\mathrm{10}\right)°\:=\:\mathrm{180}° \\ $$$$\Rightarrow\:\alpha\:+\:\beta\:=\:\mathrm{180}\:°−\:\mathrm{20}°\:−\:\mathrm{10}\:° \\ $$$$\:\:\:\:\:\:\alpha\:+\:\beta\:=\:\mathrm{150}° \\ $$

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