Question Number 83597 by dennis kenneth last updated on 04/Mar/20
$$\int_{\mathrm{0}} ^{\mathrm{2}} \left(\mathrm{3}{x}^{\mathrm{2}} −\mathrm{4}{x}+\mathrm{2}\right){dx} \\ $$
Commented by Jidda28 last updated on 04/Mar/20
![= x^3 −2x^2 +2x]_0 ^2 =(8−8+4)−0 4](Q83598.png)
$$\left.=\:\:{x}^{\mathrm{3}} −\mathrm{2}{x}^{\mathrm{2}} +\mathrm{2}{x}\right]_{\mathrm{0}} ^{\mathrm{2}} \\ $$$$=\left(\mathrm{8}−\mathrm{8}+\mathrm{4}\right)−\mathrm{0} \\ $$$$\mathrm{4} \\ $$