Question and Answers Forum

All Questions      Topic List

None Questions

Previous in All Question      Next in All Question      

Previous in None      Next in None      

Question Number 83756 by naka3546 last updated on 05/Mar/20

$$Findallrealsolutionsof(x,y)suchthat$$$$x+3y+\frac{4}{x+y}=5$$$$y+3x+\frac{5}{x+y}=7$$

Commented by Prithwish Sen 1 last updated on 05/Mar/20

$$\mathrm{adding}\mathrm{both}$$$$4(\mathrm{x}+\mathrm{y})+\frac{9}{(\mathrm{x}+\mathrm{y})}=12$$$${4\mathrm{a}}^2-12\mathrm{a}+9=0\mathbf{putting}\mathbf{x}+\mathbf{y}=\mathbf{a}$$$$\mathbf{a}=\frac{3}{2}\Rightarrow \mathbf{x}+\mathbf{y}=\frac{3}{2}...\left(\mathbf{i}\right)$$$$\mathrm{substracting}$$$$2(\mathrm{x}-\mathrm{y})+\frac{1}{\mathrm{x}+\mathrm{y}}=2$$$$\mathbf{x}-\mathbf{y}=\frac{2}{3}....\left(\mathbf{ii}\right)$$$$\mathbf{from}\left(\mathbf{i}\right)\mathbf{and}\left(\mathbf{ii}\right)\mathbf{we}\mathbf{get}$$$$\mathbf{x}=\frac{13}{12}\mathbf{and}\mathbf{y}=\frac{5}{12}$$$$\mathbf{please}\mathbf{check}$$

Commented by naka3546 last updated on 06/Mar/20

$$thankyou,sir.$$

Commented by Prithwish Sen 1 last updated on 06/Mar/20

$$\mathrm{welcome}$$

Terms of Service

Privacy Policy

Contact: info@tinkutara.com